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Math Question


Rayleigh
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ok bro...move on. We remain as he observers here and we can see where the challenges to the cerebrum remain.

 

Thanks bro, toned down my post, pls see now. Afraid I can't play any nicer than that with such err... D-Fs. :D

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Thanks bro, toned down my post, pls see now. Afraid I can't play any nicer than that with such err... D-Fs. :D

 

 

thanks. WE remain civil to those we know and how we can control our emotions is key. We remain above ourselves to do that. Those with severe blind spots, well, let the university of life take them head on

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WHAT?! Do you even understand what a ratio is? If you don't look it up.

 

A ratio of 4:7 of two quantities A and B means that A is (4/7) of B and B is (7/4) of A.

 

A is ALSO 4/(4+7) = 4/11 of the TOTAL of A and B, and B is ALSO 7/(4+7) = 7/11 of the TOTAL of A and B, which is what you're harping on and on about in your stubborn ignorance.

 

But that doesn't change the earlier part which is also completely accurate.

 

You are completely unjustified in calling ME disabled in math. That would be the pot calling the kettle black. I suggest you stop trying to "help" people in your ignorance, since you can't seem to see/admit your error after it's been amply pointed out to you.

 

EDIT: post edited in deference to RadX's wishes.

Many people got mixed up with this due to ignorance.

 

Yes, you can express the ratio 4:7 as 4/7 OR 7/4 but u can't use both in working out the ratio problem. That's why there is OR, not AND.

 

My sch teacher taught me that for ratio, A+B must be equal to 1 when you use it for working out the ratio problem.

so 4/11 + 7/11 = 11/11 = 1

 

4/7 + 7/4 is NOT = 1 as you can only express it but not use both to work out a ratio problem.

 

For radx, can you please delete my account manmaster as I do not wish to be here anymore. If you can't, pls tell me how to delete my own account. Thank you!

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Wish granted.

 

I trust you have made it good while you are here and best wishes

 

Banned!

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Cheer out guys, I know both Turboflat4 and Manmaster meant well. Let this be the platform where parents can share and seek help from the experts. Once again, many thanks to all who have contributed. My daughter is sitting for her P6 this year and you guys kindness are greatly appreciated. Have a nice evening.

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(edited)

Hi Bro of MCF, need help again for a math problem.

 

Lee spent $2992 on ties and belts. He bought 1.5 times as many ties as belts. The cost of a belt is $8 more than the cost of a tie. He paid $273 more on ties than on belts. Find the cost of a tie.

 

Partial solution and I'm stuck.

1. Amount he paid for tie is $1632

2. Amount he paid for belt is $1360.

 

Anyone can help?

Edited by Rayleigh
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Twincharged

Hi Bro of MCF, need help again for a math problem.

 

Lee spent $2992 on ties and belts. He bought 1.5 times as many ties as belts. The cost of a belt is $8 more than the cost of a tie. He paid $273 more on ties than on belts. Find the cost of a tie.

 

Partial solution and I'm stuck.

1. Amount he paid for tie is $1632

2. Amount he paid for belt is $1360.

 

Anyone can help?

 

Sure the numbers are exact? Because through models, we can easily get that the tie_total_amount = 1632.5, and belt_total_amount = 1359.5.

 

Then i got cost of tie = 32.11 but the number of ties or belts are decimal numbers which means either I'm wrong or the question's parameters are not exact. I haven't backtracked and see if the numbers all make sense adding up to total $2992.

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Sure the numbers are exact? Because through models, we can easily get that the tie_total_amount = 1632.5, and belt_total_amount = 1359.5.

 

Then i got cost of tie = 32.11 but the number of ties or belts are decimal numbers which means either I'm wrong or the question's parameters are not exact. I haven't backtracked and see if the numbers all make sense adding up to total $2992.

Thanks I have solved it. There's an error. It should be 272 not 273. Paiseh

 

Having found the total cost of ties and belt. I proceed to let u be a unit where u is the quantity of tie/belt per u. Hence.

 

ties => 1.5u => $1632 => u = $1088

belt => 1u => $1360 => u =$1360

 

Since Belt is $8 more, the ($1360-$1088)/8, each u contains 34 quantity.

 

Hence cost of a tie is 1088/34 = $32.

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Turbocharged

Hi Bro of MCF, need help again for a math problem.

 

Lee spent $2992 on ties and belts. He bought 1.5 times as many ties as belts. The cost of a belt is $8 more than the cost of a tie. He paid $273 more on ties than on belts. Find the cost of a tie.

 

Partial solution and I'm stuck.

1. Amount he paid for tie is $1632

2. Amount he paid for belt is $1360.

 

Anyone can help?

Your first part wrong -

 

He spent

$1632.50 on Ties

$1359.50 on Belts (2992/2 - 273/2)

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Twincharged

Thanks I have solved it. There's an error. It should be 272 not 273. Paiseh

 

Having found the total cost of ties and belt. I proceed to let u be a unit where u is the quantity of tie/belt per u. Hence.

 

ties => 1.5u => $1632 => u = $1088

belt => 1u => $1360 => u =$1360

 

Since Belt is $8 more, the ($1360-$1088)/8, each u contains 34 quantity.

 

Hence cost of a tie is 1088/34 = $32.

 

Yes, that gets rid of all the decimals. So I got it as well... ha ha, confirm can score A* PSLE [laugh]

 

My method is to add back the difference (272) to the belts thus making cost of ties and belts the same.

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Hi TB4 and others: i need help to solve the question below:

 

There are two tanks A and B of different capacities. If A is fill at a rate of 3L/min and B is fill at a rate of 5L/min, when A is completely filled, 5 litres of water flowed out from tank B.

 

If A is filled at a rate of 4L/min and B at a rate of 3L/min, when A is completely filled, B is only half filled. What is the capacity of B.

 

Many thanks in advance for your help.

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Long time no do algebra, dunno correct anot.. LOL

 

t= Time

 

3t = a

5t - 5 = b

b = (5/3)a - 5 --- 1

 

4t = a

3t = b/2

a = (2/3)b --- 2

 

 

Therefore, 1 = 2

 

(5/3)(2/3)b - 5 = b

10b - 45 = 9b

b = 45

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Hi TB4 and others: i need help to solve the question below:

 

There are two tanks A and B of different capacities. If A is fill at a rate of 3L/min and B is fill at a rate of 5L/min, when A is completely filled, 5 litres of water flowed out from tank B.

 

If A is filled at a rate of 4L/min and B at a rate of 3L/min, when A is completely filled, B is only half filled. What is the capacity of B.

 

Many thanks in advance for your help.

 

Sorry for the late response, just seeing this thread.

 

Here's a non-algebra way of solving:

 

From second scenario,

 

With A being filled at 4L/min and B at 3L/min, B is only half-filled when A is filled.

 

Now if A were filled at 4L/min and B at 6L/min, they would both be just-filled at exactly the same time. Hence the capacity of B is (6/4) = (3/2) that of A.

 

From first scenario,

 

In the time taken to fill A at 3L/min, if B were also filled at 3L/min, it would be (2/3) full.

 

In the time taken to fill A at 3L/min, if B were also filled at 5L/min (i.e. 5/3 as quickly), it would now be (2/3)*(5/3) = 10/9 full.

 

That's an overfill of 10/9 - 1 = 10/9 - 9/9 = 1/9 of B's capacity.

 

The volume that overflowed is 5L.

 

So 1/9 of B's capacity is 5L, hence B's capacity is 5*9 = 45L.

Edited by Turboflat4
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Bro/sis,

 

I need help for a P5 Maths question.

 

I got 3 different answers from the 3 different persons. Two of the answers are from Enrichment class teachers with many years of Maths teaching.

Thanks.

 

A) 960

B) 1210

C) 1260

D) The correct answer?

 

===============

 

Mrs Chan baked some cookies.

3/4 of the cookies were chocolate chips and the reset were almond flakes.

 

After selling 210 almond flake cookies and 5/6 of the chocolate chip cookies, she had 1/5 of the cookies left.

 

How many cookies did she sell?

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Two of the answers are from Enrichment class teachers with many years of Maths teaching. ...

 

I am shocked. Not a difficult question. [lipsrsealed]

Edited by Sosaria
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