Mllcg 3rd Gear March 7, 2012 Share March 7, 2012 1st Permutation... There are 4 Variants. Each Variant can either WIN or LOSE, for a total of 3 times. ... If a Variant WINS, the value MUST range from 2-3. If a Variant LOSES, the value MUST range from 0-1. The TOTAL number of WINS & LOSSES for all 4 Variants be add up to 6 WINS & 6 LOSSES. 2nd Permutation... Each Variant's TOTAL Value MUST range from 0-9. All 4 Variants MUST ADD up to 18. Each Variant's TOTAL Value can share the same number with another Variant. I'm looking for all POSSIBLE answers that will lead to either of the following... - A permutation that leads to 3 Variants having the same number - A permutation that leads to 2 Variants having the same number - A permutation that leads to 2 Variants having the same number, but their value is in between 2 other Variants' value. - A permutation that leads to 2 Variants having the same number, and their value is lesser than the other 2 Variants. ↡ Advertisement Link to post Share on other sites More sharing options...
Throttle2 Supersonic March 7, 2012 Share March 7, 2012 1st Permutation... There are 4 Variants. Each Variant can either WIN or LOSE, for a total of 3 times. ... If a Variant WINS, the value MUST range from 2-3. If a Variant LOSES, the value MUST range from 0-1. The TOTAL number of WINS & LOSSES for all 4 Variants be add up to 6 WINS & 6 LOSSES. 2nd Permutation... Each Variant's TOTAL Value MUST range from 0-9. All 4 Variants MUST ADD up to 18. Each Variant's TOTAL Value can share the same number with another Variant. I'm looking for all POSSIBLE answers that will lead to either of the following... - A permutation that leads to 3 Variants having the same number - A permutation that leads to 2 Variants having the same number - A permutation that leads to 2 Variants having the same number, but their value is in between 2 other Variants' value. - A permutation that leads to 2 Variants having the same number, and their value is lesser than the other 2 Variants. pardon me but Kum Pui? Link to post Share on other sites More sharing options...
Jman888 Moderator March 7, 2012 Share March 7, 2012 This one must ask 赌神！！ Link to post Share on other sites More sharing options...
Mllcg 3rd Gear March 7, 2012 Author Share March 7, 2012 This one must ask 赌神！！ ?? Link to post Share on other sites More sharing options...
Poker Neutral Newbie March 7, 2012 Share March 7, 2012 1st Permutation... There are 4 Variants. Each Variant can either WIN or LOSE, for a total of 3 times. ... If a Variant WINS, the value MUST range from 2-3. If a Variant LOSES, the value MUST range from 0-1. The TOTAL number of WINS & LOSSES for all 4 Variants be add up to 6 WINS & 6 LOSSES. 2nd Permutation... Each Variant's TOTAL Value MUST range from 0-9. All 4 Variants MUST ADD up to 18. Each Variant's TOTAL Value can share the same number with another Variant. I'm looking for all POSSIBLE answers that will lead to either of the following... - A permutation that leads to 3 Variants having the same number - A permutation that leads to 2 Variants having the same number - A permutation that leads to 2 Variants having the same number, but their value is in between 2 other Variants' value. - A permutation that leads to 2 Variants having the same number, and their value is lesser than the other 2 Variants. I suppose your questions only refer to the 2nd permutation? - A permutation that leads to 3 Variants having the same number Using trial-and-error: 0 0 0 18 (rejected) 1 1 1 17 (rejected) 2 2 2 12 (rejected) 3 3 3 9 4 4 4 6 5 5 5 3 6 6 6 0 4 different cases, with 4 combinations (4C3) for each. 4 x 4 = 16 cases - A permutation that leads to 2 Variants having the same number (never state if its single or double pair of 2 Variants) Using trial-and-error again: Single pair of 2 Variants having the same number 1 1 9 7 2 2 9 5 2 2 8 6 3 3 8 4 3 3 7 5 4 4 9 1 4 4 8 2 4 4 7 3 5 5 8 0 5 5 7 1 5 5 6 2 11 different cases, with 12 combinations (4!/2!) for each. 11 x 12 = 132 cases Double pair of 2 Variants having the same number 0 0 9 9 1 1 8 8 2 2 7 7 3 3 6 6 4 4 5 5 5 different cases, with 6 combinations (4!/(2! x 2!)) for each. 5 x 6 = 30 cases Total cases= 132 + 30 = 162 cases - A permutation that leads to 2 Variants having the same number, but their value is in between 2 other Variants' value. Eliminating from the previous question, 4 4 9 1 4 4 8 2 4 4 7 3 5 5 8 0 5 5 7 1 5 5 6 2 6 different cases, with 12 combinations (4!/2!) for each. 6 x 12 = 72 cases - A permutation that leads to 2 Variants having the same number, and their value is lesser than the other 2 Variants (never state if other 2 Variants can be the same). Eliminating from the previous 2 questions, 1 1 9 7 2 2 9 5 2 2 8 6 3 3 8 4 3 3 7 5 5 different cases, with 12 combinations (4!/2!) for each. 5 x 12 = 60 cases 0 0 9 9 1 1 8 8 2 2 7 7 3 3 6 6 4 4 5 5 5 different cases, with 6 combinations (4!/(2! x 2!)) for each. 5 x 6 = 30 cases Total= 60 + 30 = 90 cases Haha my solutions taken with a pinch of salt Link to post Share on other sites More sharing options...
Mllcg 3rd Gear March 7, 2012 Author Share March 7, 2012 cheem Link to post Share on other sites More sharing options...
Poker Neutral Newbie March 7, 2012 Share March 7, 2012 cheem you doing P and C? Link to post Share on other sites More sharing options...
Mllcg 3rd Gear March 7, 2012 Author Share March 7, 2012 you doing P and C? ya. but cheem still Link to post Share on other sites More sharing options...
Poker Neutral Newbie March 7, 2012 Share March 7, 2012 ya. but cheem still I think shld have some formula... trial and error only for desperate measures:) [where often many cases may be missed out] Link to post Share on other sites More sharing options...
Friendstar Supercharged March 7, 2012 Share March 7, 2012 What's 6 divided by 2 (1+2)? Answer 1 or 9? Link to post Share on other sites More sharing options...
Poker Neutral Newbie March 8, 2012 Share March 8, 2012 What's 6 divided by 2 (1+2)? Answer 1 or 9? If 6 divided by 2(1+2), it is 1. If 6 divided by 2, then multiply by (1+2), it is 9. The space btw 2 (1+2) is unclear:) Link to post Share on other sites More sharing options...
Sk65 1st Gear March 8, 2012 Share March 8, 2012 What's 6 divided by 2 (1+2)? Answer 1 or 9? Link to post Share on other sites More sharing options...
Mrmilktooth Supercharged March 8, 2012 Share March 8, 2012 What's 6 divided by 2 (1+2)? Answer 1 or 9? 9. using bodmas rule.. x or / will supercede + & - . so 6 / 2(1+2) = left divide 1st.. 3 ( 1+2) = 9. my 2 cents.. Link to post Share on other sites More sharing options...
Mrmilktooth Supercharged March 8, 2012 Share March 8, 2012 1st Permutation... There are 4 Variants. Each Variant can either WIN or LOSE, for a total of 3 times. ... If a Variant WINS, the value MUST range from 2-3. If a Variant LOSES, the value MUST range from 0-1. The TOTAL number of WINS & LOSSES for all 4 Variants be add up to 6 WINS & 6 LOSSES. 2nd Permutation... Each Variant's TOTAL Value MUST range from 0-9. All 4 Variants MUST ADD up to 18. Each Variant's TOTAL Value can share the same number with another Variant. I'm looking for all POSSIBLE answers that will lead to either of the following... - A permutation that leads to 3 Variants having the same number - A permutation that leads to 2 Variants having the same number - A permutation that leads to 2 Variants having the same number, but their value is in between 2 other Variants' value. - A permutation that leads to 2 Variants having the same number, and their value is lesser than the other 2 Variants. return to teacher liao.. i sux at statisitcs.. Link to post Share on other sites More sharing options...
Mustank Hypersonic March 8, 2012 Share March 8, 2012 ya. but cheem still whoa Bro, simi see P&C???? the question damm tough Link to post Share on other sites More sharing options...
Ender Hypersonic March 8, 2012 Share March 8, 2012 No wonder we need FT in Singapore to answer this type of keleng siao. Link to post Share on other sites More sharing options...
Hiphiphoray 6th Gear March 8, 2012 Share March 8, 2012 (edited) Wah kaoz......catch no balls. The only permutation i know is Spools 4D. $24 for 4 different number $12 for 2 diff number henceforth..........haha Edited March 8, 2012 by Hiphiphoray Link to post Share on other sites More sharing options...
Hiphiphoray 6th Gear March 8, 2012 Share March 8, 2012 Only 2 reply with solutions. If it was a P3 maths questions, penty ppl will cum in to hou lian. ↡ Advertisement Link to post Share on other sites More sharing options...
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