P3 Math - Help

[Geboz]

Please help to solve this P3 math using methods known to a P3 student, no algebra allowed.

 

This is too tough for me

 

Question:

Grandpa has some stamps.

If he gives 6 stamps to each of his grandchildren, he will have 5 stamps left over.

If he gives 8 stamps to each of his grandchildren, he will be short of 9 stamps.

 

a) How many grandchildren does Grandpa have ?

 

b) How many stamps fors Grandpa have ?

[Kusje]

Please help to solve this P3 math using methods known to a P3 student, no algebra allowed.

 

This is too tough for me

 

Question:

Grandpa has some stamps.

If he gives 6 stamps to each of his grandchildren, he will have 5 stamps left over.

If he gives 8 stamps to each of his grandchildren, he will be short of 9 stamps.

 

a) How many grandchildren does Grandpa have ?

 

b) How many stamps fors Grandpa have ?

 

a) (5+9)/(8-6)= 14/2=7

 

b)7*6+5 = 47

[Mits_jc]

no algebra...have to draw those bars?

 

no. of stamp ah gong hv = x

no. of ginnahs = y

 

x - 6y = 5

x - 8y = -9

2y = 14

 

y = 7

x = 47

 

Please help to solve this P3 math using methods known to a P3 student, no algebra allowed.

 

This is too tough for me

 

Question:

Grandpa has some stamps.

If he gives 6 stamps to each of his grandchildren, he will have 5 stamps left over.

If he gives 8 stamps to each of his grandchildren, he will be short of 9 stamps.

 

a) How many grandchildren does Grandpa have ?

 

b) How many stamps fors Grandpa have ?

 

[Kusje]

no algebra...have to draw those bars?

 

no. of stamp ah gong hv = x

no. of ginnahs = y

 

x - 6y = 5

x - 8y = -9

2y = 14

 

y = 7

x = 47

 

Sigh. Why make things so complicated? No need for bars or even algebra.

 

Old man wants to give 2 extra stamps to grandchildren but he lacks 9 stamps when he previously had 5 extra stamps. So just take the difference in stamps (5+9) and divide it by the number of extra stamps (2).

Edited October 20, 2009 by Kusje

[Tohto]

no algebra...have to draw those bars?

 

no. of stamp ah gong hv = x

no. of ginnahs = y

 

x - 6y = 5

x - 8y = -9

2y = 14

 

y = 7

x = 47

 

Cannot use algebra lah. P3 has not learn yet.

They using model. My daughter is also in P3, also had a hard time understand their math.

[1fast1]

Putting it in words, if grandpa gave 2 more stamps to each of his grandchildren, that would leave him with 14 stamps less (9 - (-5)). That gives 14/2 = 7 grandkids. The second part is simple, just work backward.

[Sg2303]

I believe they use guess and check method for this question.

[Geboz]

I believe they use guess and check method for this question.

 

How to guess and check ? I have never learnt this in school

Edited October 20, 2009 by Geboz

[Moozzie]

Seems like I would fail my P3 math too. Don't understand any of the explaination. Anyone can explain better? I want to learn too.

[Mechwira]

well, the below is essentially algebra done pictorially like model method...

[Sg2303]

 

This is it.

[Geboz]

Wow .. is this really taught in P3 ? Took me a while to comprehend.

 

How long is a P3 given to prepare a table like this in an exam ? By the way, this question was taken from Pei Chun primary school's past yr exam.

[Sg2303]

They should not spend more than 5 mins to draw this table.

 

I just made it clearer.

 

You can do a smaller table like this:

 

[Geboz]

Thanks ! I will show this to my son tomorrow.

He should be able to understand this, but I doubt he can produce the table in 5 minutes ... maybe in multiple of 5 minutes

[Sg2303]

Don't worry, he should be able to with practice.

[Kusje]

Seems like I would fail my P3 math too. Don't understand any of the explaination. Anyone can explain better? I want to learn too.

 

 

Ok, let me try again.

 

Imagine You have 5 dollars left. You want to give all your grandchild 2 dollars extra but that 5 dollars isn't enough; you will need 7 dollars more.

 

So in order to give your grandchildren 2 dollars more, you will need a total of $14 (5+7). That means you have 7 grandchildren (14/2).

[Arowana1]

a) (5+9)/(8-6)= 14/2=7

 

b)7*6+5 = 47

 

isnt ur (a) method algebra except u kept the x silent?

 

in algebra, u will get:

y=6x+5

y=8x-9

 

8x-9=6x+5

8x-6x=5+9

x=(5+9)/(8-6)

 

same rite? except u shortcut the equation. dats why i still dun understand why people keep saying cannot use algebra when it is still all about algerba.

[Leslielai]

My version.